Optimal. Leaf size=169 \[ \frac{e (a+b x) (d+e x)^{m+1} (b (2 B d-A e (1-m))-a B e (m+1)) \, _2F_1\left (2,m+1;m+2;\frac{b (d+e x)}{b d-a e}\right )}{2 b (m+1) \sqrt{a^2+2 a b x+b^2 x^2} (b d-a e)^3}-\frac{(A b-a B) (d+e x)^{m+1}}{2 b (a+b x) \sqrt{a^2+2 a b x+b^2 x^2} (b d-a e)} \]
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Rubi [A] time = 0.15628, antiderivative size = 168, normalized size of antiderivative = 0.99, number of steps used = 3, number of rules used = 3, integrand size = 33, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.091, Rules used = {770, 78, 68} \[ \frac{e (a+b x) (d+e x)^{m+1} (-a B e (m+1)-A b e (1-m)+2 b B d) \, _2F_1\left (2,m+1;m+2;\frac{b (d+e x)}{b d-a e}\right )}{2 b (m+1) \sqrt{a^2+2 a b x+b^2 x^2} (b d-a e)^3}-\frac{(A b-a B) (d+e x)^{m+1}}{2 b (a+b x) \sqrt{a^2+2 a b x+b^2 x^2} (b d-a e)} \]
Antiderivative was successfully verified.
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Rule 770
Rule 78
Rule 68
Rubi steps
\begin{align*} \int \frac{(A+B x) (d+e x)^m}{\left (a^2+2 a b x+b^2 x^2\right )^{3/2}} \, dx &=\frac{\left (b^2 \left (a b+b^2 x\right )\right ) \int \frac{(A+B x) (d+e x)^m}{\left (a b+b^2 x\right )^3} \, dx}{\sqrt{a^2+2 a b x+b^2 x^2}}\\ &=-\frac{(A b-a B) (d+e x)^{1+m}}{2 b (b d-a e) (a+b x) \sqrt{a^2+2 a b x+b^2 x^2}}+\frac{\left ((2 b B d-A b e (1-m)-a B e (1+m)) \left (a b+b^2 x\right )\right ) \int \frac{(d+e x)^m}{\left (a b+b^2 x\right )^2} \, dx}{2 (b d-a e) \sqrt{a^2+2 a b x+b^2 x^2}}\\ &=-\frac{(A b-a B) (d+e x)^{1+m}}{2 b (b d-a e) (a+b x) \sqrt{a^2+2 a b x+b^2 x^2}}+\frac{e (2 b B d-A b e (1-m)-a B e (1+m)) (a+b x) (d+e x)^{1+m} \, _2F_1\left (2,1+m;2+m;\frac{b (d+e x)}{b d-a e}\right )}{2 b (b d-a e)^3 (1+m) \sqrt{a^2+2 a b x+b^2 x^2}}\\ \end{align*}
Mathematica [A] time = 0.14672, size = 120, normalized size = 0.71 \[ \frac{(a+b x) (d+e x)^{m+1} \left (\frac{e (a+b x)^2 (-a B e (m+1)+A b e (m-1)+2 b B d) \, _2F_1\left (2,m+1;m+2;\frac{b (d+e x)}{b d-a e}\right )}{(m+1) (b d-a e)^2}+a B-A b\right )}{2 b \left ((a+b x)^2\right )^{3/2} (b d-a e)} \]
Antiderivative was successfully verified.
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Maple [F] time = 0.066, size = 0, normalized size = 0. \begin{align*} \int{ \left ( Bx+A \right ) \left ( ex+d \right ) ^{m} \left ({b}^{2}{x}^{2}+2\,abx+{a}^{2} \right ) ^{-{\frac{3}{2}}}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{{\left (B x + A\right )}{\left (e x + d\right )}^{m}}{{\left (b^{2} x^{2} + 2 \, a b x + a^{2}\right )}^{\frac{3}{2}}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (\frac{\sqrt{b^{2} x^{2} + 2 \, a b x + a^{2}}{\left (B x + A\right )}{\left (e x + d\right )}^{m}}{b^{4} x^{4} + 4 \, a b^{3} x^{3} + 6 \, a^{2} b^{2} x^{2} + 4 \, a^{3} b x + a^{4}}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\left (A + B x\right ) \left (d + e x\right )^{m}}{\left (\left (a + b x\right )^{2}\right )^{\frac{3}{2}}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{{\left (B x + A\right )}{\left (e x + d\right )}^{m}}{{\left (b^{2} x^{2} + 2 \, a b x + a^{2}\right )}^{\frac{3}{2}}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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